Submission #1540591

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Source Code Expand

#include <iostream>
#include <stdio.h>
using namespace std;

typedef long long LL;

int main () {
	LL a[4];
	for (int i=0;4>i;i++) cin >> a[i];
	LL n;
	cin >> n;
	LL ans=0;
	while (n>=2) {
		LL ii[4] = {a[0]*8,a[1]*4,a[2]*2,a[3]};
		LL mn = ii[0];
		for (int i=1;3>=i;i++) mn = min(mn,ii[i]);
		ans += (n/2)*mn;
		n%=2;
	}
	if (n) ans += min(min(a[0]*4,a[1]*2),a[2]);
	printf("%lld\n",ans);
}

Submission Info

Judge Result